10x^2=86

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Solution for 10x^2=86 equation:



10x^2=86
We move all terms to the left:
10x^2-(86)=0
a = 10; b = 0; c = -86;
Δ = b2-4ac
Δ = 02-4·10·(-86)
Δ = 3440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3440}=\sqrt{16*215}=\sqrt{16}*\sqrt{215}=4\sqrt{215}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{215}}{2*10}=\frac{0-4\sqrt{215}}{20} =-\frac{4\sqrt{215}}{20} =-\frac{\sqrt{215}}{5} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{215}}{2*10}=\frac{0+4\sqrt{215}}{20} =\frac{4\sqrt{215}}{20} =\frac{\sqrt{215}}{5} $

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